3x+6(3x-7)=64

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Solution for 3x+6(3x-7)=64 equation: 



3x+6(3x-7)=64

We move all terms to the left:

3x+6(3x-7)-(64)=0

We multiply parentheses

3x+18x-42-64=0

We add all the numbers together, and all the variables

21x-106=0

We move all terms containing x to the left, all other terms to the right

21x=106

x=106/21

x=5+1/21

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