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3x+5x+12=2(3x+6)
We move all terms to the left:
3x+5x+12-(2(3x+6))=0
We add all the numbers together, and all the variables
8x-(2(3x+6))+12=0
We calculate terms in parentheses: -(2(3x+6)), so:We get rid of parentheses
2(3x+6)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
8x-6x-12+12=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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