3x+5=2(2x+1)+(x-3)

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Solution for 3x+5=2(2x+1)+(x-3) equation: 



3x+5=2(2x+1)+(x-3)

We move all terms to the left:

3x+5-(2(2x+1)+(x-3))=0



We calculate terms in parentheses: -(2(2x+1)+(x-3)), so:

2(2x+1)+(x-3)

We multiply parentheses

4x+(x-3)+2

We get rid of parentheses

4x+x-3+2

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)



We get rid of parentheses

3x-5x+1+5=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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