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3x+5=(5x/2)+4
We move all terms to the left:
3x+5-((5x/2)+4)=0
We add all the numbers together, and all the variables
3x-((+5x/2)+4)+5=0
We multiply all the terms by the denominator
3x*2)+4)-((+5x+5*2)+4)=0
We add all the numbers together, and all the variables
3x*2)+4)-((5x+10)+4)=0
We add all the numbers together, and all the variables
3x*2)+4)-((5x=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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