3x+5-2(x+2)=8-3(1-x)

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Solution for 3x+5-2(x+2)=8-3(1-x) equation: 



3x+5-2(x+2)=8-3(1-x)

We move all terms to the left:

3x+5-2(x+2)-(8-3(1-x))=0

We add all the numbers together, and all the variables

3x-2(x+2)-(8-3(-1x+1))+5=0

We multiply parentheses

3x-2x-(8-3(-1x+1))-4+5=0



We calculate terms in parentheses: -(8-3(-1x+1)), so:

8-3(-1x+1)

determiningTheFunctionDomain
-3(-1x+1)+8

We multiply parentheses

3x-3+8

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

x-(3x+5)+1=0

We get rid of parentheses

x-3x-5+1=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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