3x+5+x-2=7(x+3)-2x+1

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Solution for 3x+5+x-2=7(x+3)-2x+1 equation: 



3x+5+x-2=7(x+3)-2x+1

We move all terms to the left:

3x+5+x-2-(7(x+3)-2x+1)=0

We add all the numbers together, and all the variables

4x-(7(x+3)-2x+1)+3=0



We calculate terms in parentheses: -(7(x+3)-2x+1), so:

7(x+3)-2x+1

We add all the numbers together, and all the variables

-2x+7(x+3)+1

We multiply parentheses

-2x+7x+21+1

We add all the numbers together, and all the variables

5x+22

Back to the equation:

-(5x+22)



We get rid of parentheses

4x-5x-22+3=0

We add all the numbers together, and all the variables

-1x-19=0

We move all terms containing x to the left, all other terms to the right

-x=19

x=19/-1

x=-19

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