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3x+5+2x=5(2+x)

We move all terms to the left:

3x+5+2x-(5(2+x))=0

We add all the numbers together, and all the variables

3x+2x-(5(x+2))+5=0

We add all the numbers together, and all the variables

5x-(5(x+2))+5=0

We calculate terms in parentheses: -(5(x+2)), so:We get rid of parentheses

5(x+2)

We multiply parentheses

5x+10

Back to the equation:

-(5x+10)

5x-5x-10+5=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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