3x+4x-80=x+40

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Solution for 3x+4x-80=x+40 equation: 



3x+4x-80=x+40

We move all terms to the left:

3x+4x-80-(x+40)=0

We add all the numbers together, and all the variables

7x-(x+40)-80=0

We get rid of parentheses

7x-x-40-80=0

We add all the numbers together, and all the variables

6x-120=0

We move all terms containing x to the left, all other terms to the right

6x=120

x=120/6

x=20

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