3x+4x-2=3(x+1)+4(x-1)-1

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Solution for 3x+4x-2=3(x+1)+4(x-1)-1 equation: 



3x+4x-2=3(x+1)+4(x-1)-1

We move all terms to the left:

3x+4x-2-(3(x+1)+4(x-1)-1)=0

We add all the numbers together, and all the variables

7x-(3(x+1)+4(x-1)-1)-2=0



We calculate terms in parentheses: -(3(x+1)+4(x-1)-1), so:

3(x+1)+4(x-1)-1

We multiply parentheses

3x+4x+3-4-1

We add all the numbers together, and all the variables

7x-2

Back to the equation:

-(7x-2)



We get rid of parentheses

7x-7x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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