3x+4x-1=4(x-2)

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Solution for 3x+4x-1=4(x-2) equation: 



3x+4x-1=4(x-2)

We move all terms to the left:

3x+4x-1-(4(x-2))=0

We add all the numbers together, and all the variables

7x-(4(x-2))-1=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

7x-4x+8-1=0

We add all the numbers together, and all the variables

3x+7=0

We move all terms containing x to the left, all other terms to the right

3x=-7

x=-7/3

x=-2+1/3

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