3x+4=6x2-

Solution for 3x+4=6x2- equation:

3x+4=6x^2-

We move all terms to the left:

3x+4-(6x^2-)=0

We get rid of parentheses

-6x^2+3x+4+=0

We add all the numbers together, and all the variables

-6x^2+3x=0

a = -6; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-6)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-6}=\frac{-6}{-12}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-6}=\frac{0}{-12}
=0
$