3x+47=9x+5

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Solution for 3x+47=9x+5 equation: 



3x+47=9x+5

We move all terms to the left:

3x+47-(9x+5)=0

We get rid of parentheses

3x-9x-5+47=0

We add all the numbers together, and all the variables

-6x+42=0

We move all terms containing x to the left, all other terms to the right

-6x=-42

x=-42/-6

x=+7

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