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3x+4/x=26
We move all terms to the left:
3x+4/x-(26)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
3x*x-26*x+4=0
We add all the numbers together, and all the variables
-26x+3x*x+4=0
Wy multiply elements
3x^2-26x+4=0
a = 3; b = -26; c = +4;
Δ = b2-4ac
Δ = -262-4·3·4
Δ = 628
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{628}=\sqrt{4*157}=\sqrt{4}*\sqrt{157}=2\sqrt{157}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{157}}{2*3}=\frac{26-2\sqrt{157}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{157}}{2*3}=\frac{26+2\sqrt{157}}{6} $
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