3x+4/2x=9

Solution for 3x+4/2x=9 equation:

3x+4/2x=9

We move all terms to the left:

3x+4/2x-(9)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We multiply all the terms by the denominator


3x*2x-9*2x+4=0

Wy multiply elements

6x^2-18x+4=0

a = 6; b = -18; c = +4;
Δ = b2-4ac
Δ = -182-4·6·4
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{57}}{2*6}=\frac{18-2\sqrt{57}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{57}}{2*6}=\frac{18+2\sqrt{57}}{12}
$