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3x+4-x=2(x+4)
We move all terms to the left:
3x+4-x-(2(x+4))=0
We add all the numbers together, and all the variables
2x-(2(x+4))+4=0
We calculate terms in parentheses: -(2(x+4)), so:We get rid of parentheses
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
2x-2x-8+4=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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