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3x+4(x-2)=x-5+(2x-1)
We move all terms to the left:
3x+4(x-2)-(x-5+(2x-1))=0
We multiply parentheses
3x+4x-(x-5+(2x-1))-8=0
We calculate terms in parentheses: -(x-5+(2x-1)), so:We add all the numbers together, and all the variables
x-5+(2x-1)
determiningTheFunctionDomain x+(2x-1)-5
We get rid of parentheses
x+2x-1-5
We add all the numbers together, and all the variables
3x-6
Back to the equation:
-(3x-6)
7x-(3x-6)-8=0
We get rid of parentheses
7x-3x+6-8=0
We add all the numbers together, and all the variables
4x-2=0
We move all terms containing x to the left, all other terms to the right
4x=2
x=2/4
x=1/2
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