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3x+4(3x-5)=8-5(2x+1)
We move all terms to the left:
3x+4(3x-5)-(8-5(2x+1))=0
We multiply parentheses
3x+12x-(8-5(2x+1))-20=0
We calculate terms in parentheses: -(8-5(2x+1)), so:We add all the numbers together, and all the variables
8-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+8
We multiply parentheses
-10x-5+8
We add all the numbers together, and all the variables
-10x+3
Back to the equation:
-(-10x+3)
15x-(-10x+3)-20=0
We get rid of parentheses
15x+10x-3-20=0
We add all the numbers together, and all the variables
25x-23=0
We move all terms containing x to the left, all other terms to the right
25x=23
x=23/25
x=23/25
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