3x+4(2(x+1)+5)=

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Solution for 3x+4(2(x+1)+5)= equation:


Simplifying
3x + 4(2(x + 1) + 5) = 0

Reorder the terms:
3x + 4(2(1 + x) + 5) = 0
3x + 4((1 * 2 + x * 2) + 5) = 0
3x + 4((2 + 2x) + 5) = 0

Reorder the terms:
3x + 4(2 + 5 + 2x) = 0

Combine like terms: 2 + 5 = 7
3x + 4(7 + 2x) = 0
3x + (7 * 4 + 2x * 4) = 0
3x + (28 + 8x) = 0

Reorder the terms:
28 + 3x + 8x = 0

Combine like terms: 3x + 8x = 11x
28 + 11x = 0

Solving
28 + 11x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + 11x = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 11x = 0 + -28
11x = 0 + -28

Combine like terms: 0 + -28 = -28
11x = -28

Divide each side by '11'.
x = -2.545454545

Simplifying
x = -2.545454545

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