3x+35=7x+12

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Solution for 3x+35=7x+12 equation: 



3x+35=7x+12

We move all terms to the left:

3x+35-(7x+12)=0

We get rid of parentheses

3x-7x-12+35=0

We add all the numbers together, and all the variables

-4x+23=0

We move all terms containing x to the left, all other terms to the right

-4x=-23

x=-23/-4

x=5+3/4

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