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3x+34x(5x+8x)+x(2)=24
We move all terms to the left:
3x+34x(5x+8x)+x(2)-(24)=0
We add all the numbers together, and all the variables
3x+34x(+13x)+x2-24=0
We add all the numbers together, and all the variables
x^2+3x+34x(+13x)-24=0
We multiply parentheses
x^2+442x^2+3x-24=0
We add all the numbers together, and all the variables
443x^2+3x-24=0
a = 443; b = 3; c = -24;
Δ = b2-4ac
Δ = 32-4·443·(-24)
Δ = 42537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{42537}}{2*443}=\frac{-3-\sqrt{42537}}{886} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{42537}}{2*443}=\frac{-3+\sqrt{42537}}{886} $
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