3x+3-5x=7(2x-3)-(6x-4)

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Solution for 3x+3-5x=7(2x-3)-(6x-4) equation: 



3x+3-5x=7(2x-3)-(6x-4)

We move all terms to the left:

3x+3-5x-(7(2x-3)-(6x-4))=0

We add all the numbers together, and all the variables

-2x-(7(2x-3)-(6x-4))+3=0



We calculate terms in parentheses: -(7(2x-3)-(6x-4)), so:

7(2x-3)-(6x-4)

We multiply parentheses

14x-(6x-4)-21

We get rid of parentheses

14x-6x+4-21

We add all the numbers together, and all the variables

8x-17

Back to the equation:

-(8x-17)



We get rid of parentheses

-2x-8x+17+3=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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