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3x+3(x-4)=3(3x-6)
We move all terms to the left:
3x+3(x-4)-(3(3x-6))=0
We multiply parentheses
3x+3x-(3(3x-6))-12=0
We calculate terms in parentheses: -(3(3x-6)), so:We add all the numbers together, and all the variables
3(3x-6)
We multiply parentheses
9x-18
Back to the equation:
-(9x-18)
6x-(9x-18)-12=0
We get rid of parentheses
6x-9x+18-12=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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