3x+3(3+4x)=4(5-3x)+16

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Solution for 3x+3(3+4x)=4(5-3x)+16 equation: 



3x+3(3+4x)=4(5-3x)+16

We move all terms to the left:

3x+3(3+4x)-(4(5-3x)+16)=0

We add all the numbers together, and all the variables

3x+3(4x+3)-(4(-3x+5)+16)=0

We multiply parentheses

3x+12x-(4(-3x+5)+16)+9=0



We calculate terms in parentheses: -(4(-3x+5)+16), so:

4(-3x+5)+16

We multiply parentheses

-12x+20+16

We add all the numbers together, and all the variables

-12x+36

Back to the equation:

-(-12x+36)



We add all the numbers together, and all the variables

15x-(-12x+36)+9=0

We get rid of parentheses

15x+12x-36+9=0

We add all the numbers together, and all the variables

27x-27=0

We move all terms containing x to the left, all other terms to the right

27x=27

x=27/27

x=1

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