3x+2y=5;y=-3/2x+3/4

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2x+y=8
x+3y=14

Solution for 3x+2y=5;y=-3/2x+3/4 system of equations: 


  • /| 3*x+2*y-5 = 0| y-((-3/2)*x)-(3/4) = 0
  • We try to solve the equation: 3*x+2*y-5 = 0
  • 3*x+2*y-5 = 0 // - 3*x-5
  • 2*y = -(3*x-5) // : 2
  • y = (-(3*x-5))/2
  • y = (5-(3*x))/2
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (5-(3*x))/2-((-3/2)*x)-(3/4) = 0| y = (5-(3*x))/2
  • (5-3*x)/2+(3*x)/2-3/4 = 0
  • 5/2-3/4 = 0
  • 7/4 = 0
  • 7/4 = 0
  • x belongs to the empty set
  • The system of equations does not have any solution

 

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