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3x+2x+2x(x+12)+(2x+4)=360
We move all terms to the left:
3x+2x+2x(x+12)+(2x+4)-(360)=0
We add all the numbers together, and all the variables
5x+2x(x+12)+(2x+4)-360=0
We multiply parentheses
2x^2+5x+24x+(2x+4)-360=0
We get rid of parentheses
2x^2+5x+24x+2x+4-360=0
We add all the numbers together, and all the variables
2x^2+31x-356=0
a = 2; b = 31; c = -356;
Δ = b2-4ac
Δ = 312-4·2·(-356)
Δ = 3809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{3809}}{2*2}=\frac{-31-\sqrt{3809}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{3809}}{2*2}=\frac{-31+\sqrt{3809}}{4} $
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