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3x+2x(x-5)=3
We move all terms to the left:
3x+2x(x-5)-(3)=0
We multiply parentheses
2x^2+3x-10x-3=0
We add all the numbers together, and all the variables
2x^2-7x-3=0
a = 2; b = -7; c = -3;
Δ = b2-4ac
Δ = -72-4·2·(-3)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{73}}{2*2}=\frac{7-\sqrt{73}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{73}}{2*2}=\frac{7+\sqrt{73}}{4} $
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