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3x+2=3(2+x)
We move all terms to the left:
3x+2-(3(2+x))=0
We add all the numbers together, and all the variables
3x-(3(x+2))+2=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
3x-3x-6+2=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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