3x+2=2(x-5)+7x

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Solution for 3x+2=2(x-5)+7x equation: 



3x+2=2(x-5)+7x

We move all terms to the left:

3x+2-(2(x-5)+7x)=0



We calculate terms in parentheses: -(2(x-5)+7x), so:

2(x-5)+7x

We add all the numbers together, and all the variables

7x+2(x-5)

We multiply parentheses

7x+2x-10

We add all the numbers together, and all the variables

9x-10

Back to the equation:

-(9x-10)



We get rid of parentheses

3x-9x+10+2=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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