3x+2=(2x+3)3

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Solution for 3x+2=(2x+3)3 equation: 



3x+2=(2x+3)3

We move all terms to the left:

3x+2-((2x+3)3)=0



We calculate terms in parentheses: -((2x+3)3), so:

(2x+3)3

We multiply parentheses

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

3x-6x-9+2=0

We add all the numbers together, and all the variables

-3x-7=0

We move all terms containing x to the left, all other terms to the right

-3x=7

x=7/-3

x=-2+1/3

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