3x+2/2x+3=x-14/x-5

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Solution for 3x+2/2x+3=x-14/x-5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+(2/2)*x+3 = x-(14/x)-5 // - x-(14/x)-5

3*x+(2/2)*x-x+14/x+3+5 = 0

3*x^1+14*x^-1+8*x^0 = 0

(3*x^2+8*x^1+14*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2+8*x^1+14*x^0) = 0

x^1

3*x^2+8*x+14 = 0

3*x^2+8*x+14 = 0

DELTA = 8^2-(3*4*14)

DELTA = -104

DELTA < 0

x in { } 

x belongs to the empty set

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