3x+2-4(x+1)=3(x+2)-2(5x+1)

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Solution for 3x+2-4(x+1)=3(x+2)-2(5x+1) equation: 



3x+2-4(x+1)=3(x+2)-2(5x+1)

We move all terms to the left:

3x+2-4(x+1)-(3(x+2)-2(5x+1))=0

We multiply parentheses

3x-4x-(3(x+2)-2(5x+1))-4+2=0



We calculate terms in parentheses: -(3(x+2)-2(5x+1)), so:

3(x+2)-2(5x+1)

We multiply parentheses

3x-10x+6-2

We add all the numbers together, and all the variables

-7x+4

Back to the equation:

-(-7x+4)



We add all the numbers together, and all the variables

-1x-(-7x+4)-2=0

We get rid of parentheses

-1x+7x-4-2=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1

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