3x+2+4x+5=7(X+1)

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Solution for 3x+2+4x+5=7(X+1) equation: 



3x+2+4x+5=7(x+1)

We move all terms to the left:

3x+2+4x+5-(7(x+1))=0

We add all the numbers together, and all the variables

7x-(7(x+1))+7=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

7x-7x-7+7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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