3x+2(x-5)+10=2/3(9x15)+4x

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Solution for 3x+2(x-5)+10=2/3(9x15)+4x equation: 



3x+2(x-5)+10=2/3(9x

We move all terms to the left:

3x+2(x-5)+10-(2/3(9x)=0



Domain of the equation: 39x+10!=0

We move all terms containing x to the left, all other terms to the right

39x!=-10

x!=-10/39

x!=-10/39

x∈R



We multiply parentheses

3x+2x-(2/39x+10-10=0

We multiply all the terms by the denominator


3x*39x+2x*39x+10-10+10-10-(2=0

We add all the numbers together, and all the variables

3x*39x+2x*39x=0

Wy multiply elements

117x^2+78x^2=0

We add all the numbers together, and all the variables

195x^2=0

a = 195; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·195·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{390}=0$

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