3x+2(x-3)=1/2(10x+12)

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Solution for 3x+2(x-3)=1/2(10x+12) equation: 



3x+2(x-3)=1/2(10x+12)

We move all terms to the left:

3x+2(x-3)-(1/2(10x+12))=0



Domain of the equation: 2(10x+12))!=0

x∈R



We multiply parentheses

3x+2x-(1/2(10x+12))-6=0

We multiply all the terms by the denominator


3x*2(10x+12))+2x*2(10x+12))-(1-6*2(10x+12))=0

We add all the numbers together, and all the variables

3x*2(10x+12))+2x*2(10x+12))-(1-6*2(10x=0

Wy multiply elements

12x^3(1+12))-(1-6*2(10x=0

We do not support expression: x^3(1

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