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3x+2(x+2)=22-3(2x-5
We move all terms to the left:
3x+2(x+2)-(22-3(2x-5)=0
We multiply parentheses
3x+2x-(22-3(2x-5)+4=0
We add all the numbers together, and all the variables
5x-(22-3(2x-5)+4=0
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