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3x+2(x+2)=(2x-5)
We move all terms to the left:
3x+2(x+2)-((2x-5))=0
We multiply parentheses
3x+2x-((2x-5))+4=0
We calculate terms in parentheses: -((2x-5)), so:We add all the numbers together, and all the variables
(2x-5)
We get rid of parentheses
2x-5
Back to the equation:
-(2x-5)
5x-(2x-5)+4=0
We get rid of parentheses
5x-2x+5+4=0
We add all the numbers together, and all the variables
3x+9=0
We move all terms containing x to the left, all other terms to the right
3x=-9
x=-9/3
x=-3
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