3x+2(6x-x)=9x+2(x+4)

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Solution for 3x+2(6x-x)=9x+2(x+4) equation: 



3x+2(6x-x)=9x+2(x+4)

We move all terms to the left:

3x+2(6x-x)-(9x+2(x+4))=0

We add all the numbers together, and all the variables

3x+2(+5x)-(9x+2(x+4))=0

We multiply parentheses

3x+10x-(9x+2(x+4))=0



We calculate terms in parentheses: -(9x+2(x+4)), so:

9x+2(x+4)

We multiply parentheses

9x+2x+8

We add all the numbers together, and all the variables

11x+8

Back to the equation:

-(11x+8)



We add all the numbers together, and all the variables

13x-(11x+8)=0

We get rid of parentheses

13x-11x-8=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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