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3x+2(4x-6)=7x+4(x-3
We move all terms to the left:
3x+2(4x-6)-(7x+4(x-3)=0
We multiply parentheses
3x+8x-(7x+4(x-3)-12=0
We add all the numbers together, and all the variables
11x-(7x+4(x-3)-12=0
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