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3x+2(2x+2)=2+3(2x+2)
We move all terms to the left:
3x+2(2x+2)-(2+3(2x+2))=0
We multiply parentheses
3x+4x-(2+3(2x+2))+4=0
We calculate terms in parentheses: -(2+3(2x+2)), so:We add all the numbers together, and all the variables
2+3(2x+2)
determiningTheFunctionDomain 3(2x+2)+2
We multiply parentheses
6x+6+2
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
7x-(6x+8)+4=0
We get rid of parentheses
7x-6x-8+4=0
We add all the numbers together, and all the variables
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4
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