3x+1=4(x-1)-3(x-2)

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Solution for 3x+1=4(x-1)-3(x-2) equation: 



3x+1=4(x-1)-3(x-2)

We move all terms to the left:

3x+1-(4(x-1)-3(x-2))=0



We calculate terms in parentheses: -(4(x-1)-3(x-2)), so:

4(x-1)-3(x-2)

We multiply parentheses

4x-3x-4+6

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We get rid of parentheses

3x-x-2+1=0

We add all the numbers together, and all the variables

2x-1=0

We move all terms containing x to the left, all other terms to the right

2x=1

x=1/2

x=1/2

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