3x+1=32(x-3)

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Solution for 3x+1=32(x-3) equation: 



3x+1=32(x-3)

We move all terms to the left:

3x+1-(32(x-3))=0



We calculate terms in parentheses: -(32(x-3)), so:

32(x-3)

We multiply parentheses

32x-96

Back to the equation:

-(32x-96)



We get rid of parentheses

3x-32x+96+1=0

We add all the numbers together, and all the variables

-29x+97=0

We move all terms containing x to the left, all other terms to the right

-29x=-97

x=-97/-29

x=3+10/29

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