3x+1=3(1x-1)+4

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Solution for 3x+1=3(1x-1)+4 equation: 



3x+1=3(1x-1)+4

We move all terms to the left:

3x+1-(3(1x-1)+4)=0

We add all the numbers together, and all the variables

3x-(3(x-1)+4)+1=0



We calculate terms in parentheses: -(3(x-1)+4), so:

3(x-1)+4

We multiply parentheses

3x-3+4

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

3x-3x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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