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3x+1=2-(2-2x)
We move all terms to the left:
3x+1-(2-(2-2x))=0
We add all the numbers together, and all the variables
3x-(2-(-2x+2))+1=0
We calculate terms in parentheses: -(2-(-2x+2)), so:We add all the numbers together, and all the variables
2-(-2x+2)
determiningTheFunctionDomain -(-2x+2)+2
We get rid of parentheses
2x-2+2
We add all the numbers together, and all the variables
2x
Back to the equation:
-(2x)
x+1=0
We move all terms containing x to the left, all other terms to the right
x=-1
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