3x+1=2(1x-5)

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Solution for 3x+1=2(1x-5) equation: 



3x+1=2(1x-5)

We move all terms to the left:

3x+1-(2(1x-5))=0

We add all the numbers together, and all the variables

3x-(2(x-5))+1=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

3x-2x+10+1=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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