3x+1=1+(x+2)

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Solution for 3x+1=1+(x+2) equation: 



3x+1=1+(x+2)

We move all terms to the left:

3x+1-(1+(x+2))=0



We calculate terms in parentheses: -(1+(x+2)), so:

1+(x+2)

determiningTheFunctionDomain
(x+2)+1

We get rid of parentheses

x+2+1

We add all the numbers together, and all the variables

x+3

Back to the equation:

-(x+3)



We get rid of parentheses

3x-x-3+1=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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