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3x+1=(2x-19)-10
We move all terms to the left:
3x+1-((2x-19)-10)=0
We calculate terms in parentheses: -((2x-19)-10), so:We get rid of parentheses
(2x-19)-10
We get rid of parentheses
2x-19-10
We add all the numbers together, and all the variables
2x-29
Back to the equation:
-(2x-29)
3x-2x+29+1=0
We add all the numbers together, and all the variables
x+30=0
We move all terms containing x to the left, all other terms to the right
x=-30
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