3x+19=-x+3(1+4x)

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Solution for 3x+19=-x+3(1+4x) equation: 



3x+19=-x+3(1+4x)

We move all terms to the left:

3x+19-(-x+3(1+4x))=0

We add all the numbers together, and all the variables

3x-(-x+3(4x+1))+19=0



We calculate terms in parentheses: -(-x+3(4x+1)), so:

-x+3(4x+1)

We add all the numbers together, and all the variables

-1x+3(4x+1)

We multiply parentheses

-1x+12x+3

We add all the numbers together, and all the variables

11x+3

Back to the equation:

-(11x+3)



We get rid of parentheses

3x-11x-3+19=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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