3x+12/3+X+4/5=12

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Solution for 3x+12/3+X+4/5=12 equation: 



3x+12/3+x+4/5=12

We move all terms to the left:

3x+12/3+x+4/5-(12)=0

determiningTheFunctionDomain
3x+x-12+12/3+4/5=0

We add all the numbers together, and all the variables

4x-8+4/5=0

We multiply all the terms by the denominator


4x*5+4-8*5=0

We add all the numbers together, and all the variables

4x*5-36=0

Wy multiply elements

20x-36=0

We move all terms containing x to the left, all other terms to the right

20x=36

x=36/20

x=1+4/5

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