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3x+11=2(x+3)-1
We move all terms to the left:
3x+11-(2(x+3)-1)=0
We calculate terms in parentheses: -(2(x+3)-1), so:We get rid of parentheses
2(x+3)-1
We multiply parentheses
2x+6-1
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
3x-2x-5+11=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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