3x+10x*100x=x

Solution for 3x+10x*100x=x equation:

3x+10x*100x=x

We move all terms to the left:

3x+10x*100x-(x)=0

We add all the numbers together, and all the variables

2x+10x*100x=0

Wy multiply elements

1000x^2+2x=0

a = 1000; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·1000·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*1000}=\frac{-4}{2000}
=-1/500
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*1000}=\frac{0}{2000}
=0
$